Event Planning Business Plan - 1415 Words

Business Plan Executive Summary Extravaganza is a full service company that provides complete party planning services for weddings, bridal shower, baby showers, Sweet 16 and anniversaries. Our staff is experienced and dedicated professionals with many years of party planning experience. Extravaganza listens to the customers’ needs and works with them to create the event of their dreams. We want every detail of their event to be both a pleasurable and a memorable experience. Therefore we offer a host of packages and services specifically tailored to the needs of each person. Our goal is to satisfy ever customer’s needs and let them realize that there can be a stress-free affordable way to plan a party. 2. The Business Summary†¦show more content†¦Also by using all our contacts and resources in the area, that we have relationships with, we save the customer money. Since there are not many party planning companies in Jersey City it will make it easier for us to get most of the business in the area. Extravaganza is in a unique position of competition. We compete against other event planners that are probably much larger, hotels that have their own space for the event and people who just do it on their own. The hotels have an advantage and that is that they already have a staff in house, they are able to provide many services in one location. But the downfall is that they have so much going on that errors are bound to happen. Also it can be very costly. Other event planners have an advantage because they have been in the industry much longer and probably have more clients. People who decide to it on their own can manage the cost of the event and add personal touches to the party. The only thing is that it is very time consuming and they might not have the resources needed when it comes to pricing, service, etc†¦ Marketing Plan To have a successful marketing strategy we will look at our competitors and see how it works for them and see if there are ways to improve it to benefit us. We need to see where their weakness lies and try not to follow the same pattern. There are many ways to advertise and promote our business such as:  · Web  · Trade Shows  ·Show MoreRelatedEvent Planning Business Plan Essay1399 Words   |  6 PagesBusiness Plan Executive Summary Extravaganza is a full service company that provides complete party planning services for weddings, bridal shower, baby showers, Sweet 16 and anniversaries. Our staff is experienced and dedicated professionals with many years of party planning experience. Extravaganza listens to the customers’ needs and works with them to create the event of their dreams. We want every detail of their event to be both a pleasurable and a memorable experience. Therefore we offerRead MoreEvent Planning1078 Words   |  5 PagesEvent Planning Carson Stokes English Honors 4B – Stephens March 29, 2012 Carson Stokes English Honors – Stephens March 29, 2012 The Wonderful World of Event Planning What is event planning? Other than my dream job, event planning is the process of planning special occasions such as – but not limited to – fairs, parades, weddings, reunions, sweet sixteen’s, birthdays, graduations, conferences, political rallies, fashion shows, and memorials. Event planning includes budgeting, establishingRead MoreContinuity Of Government And Continuity Essay842 Words   |  4 Pagesgovernment and continuity of operations. Business continuity encompasses a loosely defined set of planning, preparatory and related activities which are intended to ensure that an organization’s critical business functions will either continue to operate despite serious incidents or disasters that might otherwise have interrupted them, or will be recovered to an operational state within a reasonably short period. Resilience critical business functions and the supporting infrastructure areRead MoreThe Benefits and Limitations of Strategic Planning for Organizations1722 Words   |  7 PagesLimitations of Strategic Planning for Organizations It was August of 1914 and Germany had committed virtually its entire army to the invasion of Belgium and France. Few German troops remained to defend East Prussia against the invasion of two huge Russian armies. Despite the numerical inferiority, Colonel Hoffmann, chief of the German Eighth Army staff, created an audacious strategy to surround and annihilate one of the Russian armies. He began to plan a detailed attackRead MoreIncident Response Plan And A Disaster Recovery1591 Words   |  7 PagesQuestion 1: First, Incident Response (IR) plan â€Å"is a detailed set of processes and procedures that anticipate, detect, and mitigate the effects of an unexpected event that might compromise information resources and assets.† (Whitman, 2013, p. 85). Consequently, Incident response planning (IRP) is the planning for an incident, which occurs when an attack affects information systems causing disruptions. On the other hand, Disaster Recovery (DR) plan â€Å"entails the preparation for and recovery from aRead MoreDisasters Are Not Always Preventable, But There Are Methods1576 Words   |  7 Pagesunforeseen event involving damage or injury† (OED Online). There are two types of disasters. A natural disaster when events are not caused by human interaction. There is also a man-made disaster; these disasters are caused deliberately by humans. 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Overall, low-fair air transport was hit the hardest, losing 61 per cent of flights over the an 8 day period. This was due to a less flexible and poor business model and higher geographical exposure. An estimation of seven million passengers wereRead MoreCritical Success Factors For Organizing Activities1346 Words   |  6 PagesMore specifically, with a good budget planning and value management, NAWMBA can easily attract more funding from outside supporters. 2. Get more members to join the NAWMBA WPI Chapter Tactical planning such as service level planning, application planning, and data planning can help NAWMBA attract more members because they can effectively improve the charms of NAWMBA so as to gain more members 3. Collaboration with other student associations Tactical planning can greatly improve NAWMBA work efficiency

Systemic Lupus Erythmatosus Essay example - 1364 Words

Lupus is a chronic inflammatory disease that occurs when your body’s immune system attacks your own tissues and organs. The inflammation caused by lupus can affect many body systems including the following: joints, skin, kidneys, blood cells, heart and lungs. Lupus occurs more frequently in women than in men. There are four different types of Lupus that exist. They are Systemic lupus erythematosus, Discoid lupus erythematosus, Drug-induced erythematosus, and Neonatal lupus. The most common and most serious type is Systemic lupus erythematosus. Previously the outlook for people with lupus was grim, but diagnosis and treatment of lupus has improved quite a bit. With proper treatment, most people can lead happy and active lives. This†¦show more content†¦Lupus is a very complex disease that requires knowledge and awareness on the part of the doctor and good communication from the patient. There is no single test that can determine if a person has lupus. Several laboratory tests can help a doctor confirm the diagnosis of SLE or rule out other causes for the person’s symptoms. The ANA (antinuclear antibody) test is commonly used. This test looks for antibodies that react against the components of the nucleus of the body’s cells. The doctor can also order a biopsy of the kidney’s or the skin if those body parts are affected. The doctor can also order a test for anticardiolipin antibodies. If the person is found to have these than they are at an increased risk for blood clotting and there is an increased risk of miscarriages for pregnant women. Other testing that may be done is a complete blood count, urinalysis, blood chemistries, and erythrocyte sedimentation rate test (a test that measures inflammation). In order for a doctor to diagnose you with SLE, you must have 4 out of 11 typical signs of the disease. SLE may alter the results of the following tests: Antithyroglobulin antibody, Antithyroid microsomal antib ody, Complement components (C3 and C4), Coombs’ test-direct, Cryoglobulins, ESR, Kidney function blood tests, Liver function blood tests and Rheumatoid factor. (Makeover, 1997) There are no two cases of SLE that are like. Symptoms may come on suddenly or develop slowly. The symptoms may be mildShow MoreRelated Lupus Essay1079 Words   |  5 Pages Lupus Definition of the Disease Lupus is a chronic inflammatory disease of unknown cause that can affect virtually any part of the body. The medical term for Lupus is Systemic Lupus Erythematosus or better known as SLE. With Lupus there is a malfunction in some of the cells of the immune system. quot;In Lupus, the body overreacts to an unknown stimulus and makes to many antibodies, or proteins directed against body tissue. Thus, Lupus is called an autoimmune disease. †# Myth/Reality StatementsRead MoreA Woman Doing Life : Notes From A Prison For Women1320 Words   |  6 PagesGeorge was diagnosed with systemic lupus erythmatosus (SLE). Upon her arrival to Fluvanna George reported to the medical staff that she had SLE but it was never written on her medical profile until she had a freak accident. While in the shower George lupus symptoms attacked her and she fell and injured herself in the shower. When she was seen by the prison s doctor they did not believe she had lupus because the doctor declared that only African Americans can get lupus. George s medical case still

Tutorial answers Free Essays

If the system already exists, different scenarios can be tried using he model before tests being carried out on the real system. Alternatively if the system does not exist, the model can be used to help decide on the final design of a system. Often there are constraints on the design that need to be investigated e. We will write a custom essay sample on Tutorial answers or any similar topic only for you Order Now G. Constraints on cost, space, etc. Modification to systems once they exist can be expensive hence it is important to try and get design of systems ‘right-first-time’ and this is where modeling and simulation can be useful engineering tools. Example: see lecture notes weekly under section Why is modeling important ?. 2 See notes 3. Components of system Inputs Outputs States Environment Tank Valve Pipes Inlet Flows of A and B Liquid level Level change in tank Upstream of inlet to tank and downstream of outlet valve 4. See notes 5. See notes 6. Bookwork (as coursework 1) TUTORIAL ANSWERS 2 El . A proportional relationship for a component is here considered to be an unchanging relationship (and is often referred to in modeling terms as a constitutive or physical relationship). These are the natural physical laws which the individual components of the system obey e. G. For an electrical system, the relationship between voltage and current and in the special case of an ideal resistor – Ohm’s Law FRR. I E. Kerchiefs Current Law : algebraic summation of all currents flowing into a junction of a network is zero. Kerchiefs Voltage Law: algebraic summation of all voltages acting around a loop of a circuit is zero. Examples – see section 2. 2. Of lecture notes. E. The impedance of an element is its voltage:current ratio. Multiple Choice: Electrical Systems El(b) E(C) Problems: Electrical Systems El . 3. 3 0, Ohm’s Law is obeyed since the resistance is constant as the voltage varies Q. 40 A E. IV E. (a) 4. 4 0 (b) 16 (c) 4. 4 E. (a) 0. 68 V (b) 0. 47 V (c) 0. 34 V E. (a) 0. 2 V, 205 ma (b) 1. 03 V, 52 ma (c) 1. 16 V, 193 ma E. = 30/84 v = 0. 357*12 volts = 4. Volts E. VI = 366/191 = 1. 92 V, TUTORIAL ANSWERS 3 MI . (I) spring f = xx= k(XSL -xx) where x is the displacement (or extension) and k is the proportionality constant called the spring constant with units of force/displacement e. . N/m. Damper f = BE k(FL – vi) where v is the velocity and B is the proportionality constant called a viscous friction coefficient or constant. Its dimension is force/velocity e. G. NSA/m. MM. See lecture notes. The force balance law demands that (a the acceleration). Analogies: This is analogous to Kerchiefs voltage law, particularly if one treats the inertia acceleration as an equivalent force. Note: In order to model a mechanical system, the usual practice is to form a free body diagram around each inertia (mass) component. One will then end up with a set of simultaneous differential equations, the solution of which dictates the dynamics and constitutes the system model. In the case where there are no mass components, then ensure a force balance at selected points in the system. That is the net force acting on any point must be zero, I. E. Multiple Choice: Mechanical Systems MI . G) MM. (a,b) Problems: Mechanical Systems MI. O. AN MM. 0. 05 arms Question/ Variable (NSA/m) 812 834 Biota I 2 1217 24/19= 1 . 263 4 15/8 60/47 = 1 . 276 Questions: Thermal and Fluid Systems TFH . A system is said to be in equilibrium when its behavior is steady I. E its output and inputs are unchanging. For the liquid level system with an inlet and outlet flow, this corresponds to the inlet and outlet flows being the same. Multiple Choice: Thermal and Fluid Systems TFH. (b) TFH. (c) Problems: Thermal and Fluid Systems TFH . The flow cannot be assumed to be laminar as the proportionality constant is not inner as the flow increases through the pipe I. E. I/R resistance (Pa. s/mm) 3 TUTORIAL ANSWERS 4 IQ . Methods that can be used to determine the gradient of the straight line at t=2 sec are: (I) plot a graph and determine where t=2 or (it) differentiate x(t) with respect to t and substitute t=2. Q. (a) Q. See lecture notes Q. Completing the table gives: Electrical Component Equation Mechanical Component Rotational Component Inductor Inertia Rotating inertia Resistor Damper Capacitor Spring Torsion’s spring Q. (a) Using free body diagram on the mass-damper system of Fig. 5. 1, the mass and ampere can be considered to be in parallel. Force balance gives: where: Hence: (b) Similarly for the spring-damper system of Fig. 5. 2 Force balance gives: where: , (c) For the rotational pulley of Fig. 5. 3, a torque balance is required: Torque balance gives:and where:, , Q. (a) For a resistor and capacitor in series of Fig. 6. 1 Apply Kerchiefs Voltage Law gives: (b) For a resistor and inductor in series of Fig. 6. 2 where: , , (c) For a 5 resistors and a capacitor system of Fig. 6. 3, observe that this is nearly the same system as shown in Tutorial Sheet 2 Problem E but with the addition of the opacity. Hence: where: with and Hence as in Qua. : Q. Q. Material balance on tank: rate of change of mass floodwater = mass flow in – mass flow out assume constant density 0 and area: Given: , A = 7 mm, R = 0. 14 her/mm and Sin = 100 mm/her substituting gives: Tutorial Answers 5, 6 IQ Bookwork straight from notes: Ask in a tutorial if stuck and/or use MENTAL to generate solutions and check against you work. E. G. For 1st of these t=alliances(O,2,100); ext=subs(x,t); fugue(l reset Q: Throughout Q assume a model of the form Steady-state is 0. 6. Initial value is -1. Rise is given as 1. . 63% of rise is given by which implies x(t) has this value at about t=O. 25 sec and therefore T=O. 25, Steady-state is 30. Initial value is 2. Rise is given as 28. 63% of rise is given by 0. 63*28=17. 64 which implies x(t)=19. 64. X(t) has this value at about t=5 sec and therefore T=5, k=30. Steady-state is 50. Initial value is 20. Rise is given as 30. 63% of rise is given by 0. 63*30=18. 9 which implies x(t)=38. 9. X(t) has this value at about t=50 sec and therefore T=50, k=50. Q: Maximum current is at t=O and given as V/R: Therefore R=V/I = 5/0. 004 = mashes. Time constant is given by ARC, so T=ms implies that C=. 005/1250 = 4 micro. Q: Parameters give a time constant of cosec so after 30 sec aircraft at 95% of steady-state land speed. 1 MPH is the same as mutterer pH or (1609/3600)m/s MPH is the same as mom/s Steady-state is given as f/B. Therefore min f required is BIB [ scaled by (11. 95) to be precise]. Q: Model is Bad/dot +xx=f or (B/k) DXL/dot +x =f/k Desired time constant is about 0. Sec, therefore (B/k)=O. 8 so k=NON/m Steady-state displacement is given as (1 /k)f = 0. 04, and therefore f=AN is required. Tutorial Answers 7 1 . Find the Lovelace transform of the following signals: Students should use MENTAL to check their working here, e. G. Ray the command: 2. Use partial fractions, a lookup table and inverse Lovelace to find the underlying signals with the following transforms. Students should use MAT to check their working, e. G. 3. What is the final value for signals with the following transforms? Use the Pit but note that: (I) there is no final value if the signal is divergent which is the case for 5th (obvious from negative sign) and (it) for convergent signals, the final value must be zero if there is no integrator. Hence only 2nd and 6th have a non-zero values which must be 4 and 0. 5 respectively. 4. Which of the following transforms has the fastest settling time? What are the settling times to within 5% of steady-state? Time constants are negative inverses of poles. One can estimate time to 5% error as approximately three times slowest time constant (exact for 1st order but no strict generalization when many poles due to uncertainty about partial fractions). Time constant is the negative inverse of the pole. So pole at -0. 25 gives T=4, etc. 5. Sketch the poles and zeros of the following transforms on an Regard diagram. By marking the LAP and RAP clearly, hence determine which represent stable and unstable behavior. Students should use MENTAL to check their working for his, for example, doing 4th as follows will produce a fugue with poles marked in Y and zeros in ‘o’: Systems are stable if and only if all the poles are in the LAP – the origin is counted as being in the LAP. The positions of the zeros do not affect stability. Tutorial Answers 8 1 . The inverse Lovelace transform of a transfer function is called the â€Å"impulse response function†. If a system has an impulse response function given by g(t) t(l-sin(t)). Compute its transfer function, G(s). 2. Use Lovelace methods to solve the following ODE equations. 3. Give examples of type O, type 1 and type 2 systems. Has does this affect the expected behavior? Bookwork 4. Which of the following transforms for 1st order ODES has the highest gain? What are the gains? What are the time constants? Determine and sketch the step responses for each of these. Gains are 4, 3, 1. 5 and 1. 125 respectively. Time constants are 4, 0. 2, 1. 25, 0. 5 respectively. As these are 1st order, sketching step response follows same procedures as tutorial 5,6. Tutorial Answers 9, 10 1 . Bookwork – read some control text books to broaden your views on the uses and potential of control. 2. This is also straight from the notes but your understanding will also be improved by some wider reading. Don’t Just stick to your main discipline, but look at examples from chemical, aerospace, automotive, medical, electrical, biological, etc. 3. Straightforward application of the Pit. 2nd set has an integrator and hence the offset is known to be zero. Otherwise, use formula. Confirm this with MENTAL, I. E. Plot is seen to settle at 0. 52 4. The 1st part is taken direct from the lecture slides so not repeated here. The closed-loop time constant and rise time are: Time constant +AKA), closed-loop game = AKA/(I+AKA), where A=4/5, -r=o. 2 Hence 0. 2/(1 +K/5)O. 8 which gives K 4+3. K or 0. K4 or K5. Confirm this using MENTAL, ii. Use G=TFH(4,[1 %% plot in a figure It is clear that the time closed loop pole polynomial is (s+ [1 +AKA]/T) and hence the pole is in the LAP for all positive K which implies closed-loop stability. Discussion of large K is bookwork – read some text books. 5. This question is designed to make a student think and experiment. To meet specifications, the closed-loop is given as Clearly the steady-state gain is unity as expected so the offset requirement is met. The closed-loop poles are determined from the roots of the denominator and we want the poles to be to the left of -2. 5 ‘e. (s+2. 5) is equivalent to (0. As+1). Both roots can be placed at 2. 5 if In the future students will recognize that lower values of K will give a slower pole and higher values of K will give rise to oscillation. 6. Standard question. Form closed-loop transfer function and find characteristic polynomial for all 3 cases. You will need to do the partial fractions for all 3 and sketch, but you can use MENTAL to check your answers. E. G form the three closed-loop transfer functions and then type feedback(GO,GO,GO) to see all 3 together. N.B.: 63 is seem 2 content. Clearly Just proportional is fastest, but gives a large offset. GIG is smooth (2 real poles) ND no offset. But poles are well spaced so this is conservative. 63 has similar response time to GIG (same slowest time constant), but has complex poles and thus oscillation. Conclusion, PI is best! Typical exam type question outline answer a) Let the internal temperature be given as T degrees. The rate of heat supplied is given as: The heat loss OHIO(T+50) Hence the temperature is given by: In steady-state we desire T=20 which implies that b) If the external temperature drops by 10 degrees, then the model becomes: which implies the new steady-state temperature will be 6 degrees! The time constant is clearly 1000 sec. Students should sketch a graph showing the temperature moving from 20 to 6 with the appropriate time constant. ) If the heat input from the passengers is increased, the model becomes In the case, the change in temperature is negligible which suggests that for this scenario the key factor is the external temperature and heaters rather than any heat coming from the passengers. D) Clearly the open-loop choice of voltage does not maintain the temperature correctly in general and so some control is needed. It is known that the correct steady-stat e can only be achieved in the presence of uncertainty if integral action is included. The steady-state error too change in desired temperature is given by because K(O) is infinite, irrespective of changes in the gain of G or disturbances such as changes in external temperature! Students should first put the equations for the model and integral control law into Lovelace transforms about the steady-state: Hence The closed-loop transfer function is given as Students should validate that the time constants are reasonable and that the closed- loop is stable! The time constants are given from the roots of the closed-loop denominator. Students should note that these are similar to the original time constant and thus satisfactory. How to cite Tutorial answers, Papers